Math Is Fun Forum

mathxyz

Member

From: Brooklyn, NY

Registered: 2024-02-24

Posts: 1,053

Bag of Gumdrops

Adam has a bag containing four yellow gumdrops and three red gumdrops. He will eat one of the gumdrops, and a few minutes later, he will eat a second gumdrop.

1) What is the probability that Adam will eat a yellow gumdrop first and a red gumdrop second?

2) What is the probability that Adam will eat two yellow gumdrops one after the other?

Let me see.

Part 1

A = probability of eating one gumdrop.

B = probability of eating one red gumdrop.

P(A) = 4/7

P(B) = 3/6

P(A n B) = P(A) • P(B)

P(A n B) = (4/7) • (3/6)

Is this right?

Part 2

A = probability of eating one yellow gumdrop.

B = probability of eating another yellow gumdrop.

P(A) = 4/7

P(B) = 3/6

P(A n B) = P(A) • P(B|A)

P(A n B) = (4/7) • (3/6)

3) What is the probability that Adam will eat two gumdrops with the same color?

I don't know how to set this one up. Any ideas?

4) What is the probability that Adam will eat two gumdrops of different colors?

Can someone set this one up for me?

Bob

Administrator

Registered: 2010-06-20

Posts: 10,627

Re: Bag of Gumdrops

Parts 1 and 2 correct.

You've done 2 yellows. Find also 2 reds, then add the two  answers to get P(two same colour)

Last part: Add P(red then yellow) to P(yellow then red)

Bob

---

Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob

mathxyz

Member

From: Brooklyn, NY

Registered: 2024-02-24

Posts: 1,053

Re: Bag of Gumdrops

Parts 1 and 2 correct.

You've done 2 yellows. Find also 2 reds, then add the two  answers to get P(two same colour)

Last part: Add P(red then yellow) to P(yellow then red)

Bob

Cool. I can do that later. Thank you.