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#1 2024-05-14 14:00:19

mathxyz
Member
From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Bag of Toy Cars

Gilligan has a bag of toy cars. He has 4 red cars, 5 blue cars and 6 pink cars. There are 15 cars in total. What is the probability (with replacement) of randomly selecting a red car, a blue car and a pink car in that order?


Let me see.


I want P(red, blue, pink).


A = probability of selecting red car.

B = probability of selecting blue car.

C = probability of selecting pink car.

P(A) = 4/15

P(B) = 5/15

P(C) = 6/15

P(A, B, C) = P(A) • P(B) • P(C)

P(A, B, C) = (4/15) • (5/15) • (6/15)

Is this correct?

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#2 2024-05-14 15:17:47

Bob
Administrator
Registered: 2010-06-20
Posts: 10,627

Re: Bag of Toy Cars

Correct

B


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2024-05-15 02:44:40

mathxyz
Member
From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Re: Bag of Toy Cars

Bob wrote:

Correct

B

Beautiful.

Today:

1. Probability of AT LEAST.

2. Probability of an event not happening.

3. Return to my college algebra textbook.

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