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#1 2024-05-17 04:38:28

mathxyz
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From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Square ABCD Inside Circle O

Square ABCD lies inside circle O. Square ABCD and circle O are both shaded. Find the area of the shaded region.


Let me see.



1. Find the hypotenuse of the square inside circle O given the lengths to be 2 by 2


2. The hypotenuse is the diameter of circle O.


3. Finding the area of circle O should give me the answer since both figures are shaded.


Yes?

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#2 2024-05-17 05:35:09

Bob
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Registered: 2010-06-20
Posts: 10,627

Re: Square ABCD Inside Circle O

Yes, except I'm confused that both shapes are shaded.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#3 2024-05-17 10:05:48

mathxyz
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From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Re: Square ABCD Inside Circle O

Bob wrote:

Yes, except I'm confused that both shapes are shaded.

Bob

A square lies in a circle. The sides of the square are actually line segments for the circle. Both figures are shaded.

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#4 2024-05-18 03:37:58

mathxyz
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From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Re: Square ABCD Inside Circle O

Bob wrote:

Yes, except I'm confused that both shapes are shaded.

Bob


Problem 39; page 37.


I think I have to add the areas.


I must find the hypotenuse if the circle.


NOTE: I NAMED THE CIRCLE USING THE LETTER O.


Let d = diameter.


2^2 + 2^2 = d^2 = hypotenuse.


8 = d^2


2•sqrt{2} = d


diameter = 2r, the radius.


2•sqrt{2} = 2r


2•sqrt{2}/2 = r


sqrt{2} = 2


Let A_r = area of shaded region.


A_r = pi•(sqrt{2})^2 + 2^2


A_r = 2pi + 4


Yes?

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#5 2024-05-18 05:04:15

Bob
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Registered: 2010-06-20
Posts: 10,627

Re: Square ABCD Inside Circle O

Again it is a great help to have the page ref.

You have got the diameter correct as root(8)  + root(4) x root(2) = 2root(2)

So the radius is root(2) that's all you need as the shaded area is a circle so youcan forget the square now. You only needed it for that diagonal.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#6 2024-05-18 05:56:58

mathxyz
Member
From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Re: Square ABCD Inside Circle O

Bob wrote:

Again it is a great help to have the page ref.

You have got the diameter correct as root(8)  + root(4) x root(2) = 2root(2)

So the radius is root(2) that's all you need as the shaded area is a circle so youcan forget the square now. You only needed it for that diagonal.

Bob

Copy.


Shaded area = pi•(sqrt{2})^2


Shaded region = 2pi.


Yes?

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#7 2024-05-18 06:08:05

Bob
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Registered: 2010-06-20
Posts: 10,627

Re: Square ABCD Inside Circle O

yes.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

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#8 2024-05-18 06:12:44

mathxyz
Member
From: Brooklyn, NY
Registered: 2024-02-24
Posts: 1,053

Re: Square ABCD Inside Circle O

Bob wrote:

yes.

Bob


Beautiful.  Math is great. I never get tired of this stuff. Yes, I am a math nerd and proud to be. I enjoy learning stuff that others hate and fear. Math has a way of humbling the proud. This is why students hate it.

Last edited by mathxyz (2024-05-18 06:13:39)

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