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#1 2024-05-20 14:40:32
- mathxyz
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- From: Brooklyn, NY
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Extra Factor Completely
Factor each polynomial completely. If the polynomial cannot be factored, say it is prime.
Problem 118; page 58.
7(x^2 - 6x + 9) + 5(x - 3)
7(x - 3)(x - 3) + 5(x - 3)
GCF = (x - 3)
(x - 3)[(7(x - 3) + 5]
(x - 3)[7x - 21 + 5]
(x - 3)(7x - 16)
You say?
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#2 2024-05-20 19:14:15
- Bob
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- Registered: 2010-06-20
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Re: Extra Factor Completely
Correct.
B
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob 
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#3 2024-05-21 01:02:12
- mathxyz
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- From: Brooklyn, NY
- Registered: 2024-02-24
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Re: Extra Factor Completely
Bob wrote:
Correct.
B
Smooth sailing as they say in the Navy. Speaking of the Navy, I miss my time there as well as I miss my youth.
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