Find (B U C)^c

harpazo65 · 2024-09-08 02:38:06

Let (B U C)^c = the complement of B union C.

U = {0, 1, 2, 3, 4, 5}

B = {2, 3, 4}

C = {1, 3, 4, 6}

B U C = {2, 3, 4} U {1, 3, 4, 6}

B U C = {1, 2, 3, 4, 6}

(B U C)^c = {0, 5}

I believe this to be right.

Bob · 2024-09-08 04:48:35

Again we have a rogue 6 in C.

Bob

harpazo65 · 2024-09-08 08:36:39

Bob wrote:

Again we have a rogue 6 in C.
Bob

Ok. I better pay close attention when typing my elements into the sets.
What do you mean by "rogue 6"?

Bob · 2024-09-08 23:56:13

Dictionary.com defines rogue as "no longer obedient, belonging, or accepted ". 6 doesn't obey the rules as it's not in the universe.

Let's get more practice by making C = {1, 3, 4, 5}

That does change your previous answer.

Bob

harpazo65 · 2024-09-09 02:20:50

Bob wrote:

Dictionary.com defines rogue as "no longer obedient, belonging, or accepted ". 6 doesn't obey the rules as it's not in the universe.
Let's get more practice by making C = {1, 3, 4, 5}
That does change your previous answer.
Bob

It changes my previous answer because 3, 4, and 5 are in the universal set U.

Math Is Fun Forum

#1 2024-09-08 02:38:06

Find (B U C)^c

#2 2024-09-08 04:48:35

Re: Find (B U C)^c

#3 2024-09-08 08:36:39

Re: Find (B U C)^c

#4 2024-09-08 23:56:13

Re: Find (B U C)^c

#5 2024-09-09 02:20:50

Re: Find (B U C)^c

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