Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2024-09-09 02:53:57

harpazo65
Member
From: Brooklyn, NY
Registered: 2024-09-07
Posts: 52

Find Domain...A

Find the domain for each expression.

1.  (x^2 + 5x - 10)/(x^3 - x)

2. (-9x^2 - x + 1)/(x^3 + x)

==============================


Question 1

(x^2 + 5x - 10)/(x^3 - x)


Set denominator to 0.

x^3 - x = 0

x(x^2 - 1) = 0

x = 0

x^2 - 1 = 0

x^2 = 1

sqrt{x^2} = sqrt{1}

x = -1, x = 1

Domain = {x | x cannot be 0, -1, or 1}


Question 2

(-9x^2 - x + 1)/(x^3 + x)

Set denominator to 0.

x^3 + x = 0

x(x^2 + 1) = 0

x = 0

x^2 + 1 = 0

When I subtract -1 from both sides of the equation, it leads to a situation involving complex numbers. The current chapter and section in the textbook does not ask for complex roots. So, I will say that x^2 + 1 is rejected.

Domain = {x | x cannot be 0}


Focus on the journey for there will be those who would love to see you fall.

Offline

#2 2024-09-18 16:14:50

Oculus8596
Banned
From: Great Lakes,Illinois
Registered: 2024-09-18
Posts: 126

Re: Find Domain...A

Your work looks correct.


The best things in life are not always free.

Offline

Board footer

Powered by FluxBB