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#1 2024-09-24 02:57:11

Oculus8596
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From: Great Lakes,Illinois
Registered: 2024-09-18
Posts: 126

Creepy Mathematics?

Find a clock in your house. The numbers given in a clockwise rotation are as follows: 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and back to 12.

From the numbers given in your clock, do this:

12 + 1 = 13


11 + 2 = 13


10 + 3 = 13


9 + 4 = 13


8 + 5 = 13


7 + 6 = 13


Creepy? Coincidence? Mysterious?


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#2 2024-09-24 04:03:54

Bob
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Registered: 2010-06-20
Posts: 10,583

Re: Creepy Mathematics?

The first number in each sum is decreasing by 1 and the second number is increasing by 1. So I would expect the total to stay constant.

In general if a + b = c  then (a+1) + (b-1) = c and more generally still, (a + n) + (b - n) = c for all n.

Bob


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#3 2024-09-24 12:03:58

Oculus8596
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From: Great Lakes,Illinois
Registered: 2024-09-18
Posts: 126

Re: Creepy Mathematics?

Bob wrote:

The first number in each sum is decreasing by 1 and the second number is increasing by 1. So I would expect the total to stay constant.

In general if a + b = c  then (a+1) + (b-1) = c and more generally still, (a + n) + (b - n) = c for all n.

Bob

Thank you for a general formula explaining the clock number structure.


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