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∫(sinc^2)4f df ,where integral range -∞ to +∞
Thanks~~!!
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If you're integrating with respect to f, then isn't sin²c just a constant?
If so, you can move it outside the integral and have sin²c∫4f df.
4f integrates quite easily, into 2f² +c.
But then if you're integrating between +∞ and -∞, then your answer would be 0.
So I could well have misinterpreted something.
Why did the vector cross the road?
It wanted to be normal.
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He means the sinc function sinc(x).
http://mathworld.wolfram.com/SincFunction.html
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