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#1 2005-05-08 23:45:55
- tOmd
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- Registered: 2005-05-08
- Posts: 1
Here's some Calculus!
How do I differentiate At^b * e^c?
Where t is the variable, e is euler's number and A, b and c are all constants. I'm pretty sure I should be able to be able to simplify it to t = b/c or something like that.
Please Help!!!
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#2 2005-05-09 00:46:34
- MathsIsFun
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- Registered: 2005-01-21
- Posts: 7,713
Re: Here's some Calculus!
Hmmm ... if you treat (A*e^c) as a constant, call it "f" then you have:
f t^b
which is easily differentiated as
f t^b ln(b)
(derivative of a^x = a^x ln a)
There may be something special with your formula that I am not aware of, though!
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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