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Simplifying Simple i Terms - Intermediate Level
Express in simplest terms, in terms of i.
1. i[sup]1[/sup]
2. i[sup]3[/sup]
3. i[sup]0[/sup]
4. i[sup]19[/sup]
5. (i[sup]12[/sup])[sup]15[/sup]
6. i[sup]16[/sup] + i[sup]11[/sup]
7. i[sup]18[/sup] + i[sup]13[/sup]
8. (i[sup]6[/sup])[sup]30[/sup]
9. i[sup]25[/sup] - i[sup]20[/sup]
10. i[sup]29[/sup] × i[sup]14[/sup]
11. i[sup]23[/sup]
12. i[sup]36[/sup] ÷ i[sup]32[/sup]
13. i[sup]37[/sup] - i[sup]2[/sup]
14. (i[sup]28[/sup])[sup]33[/sup]
15. i[sup]8[/sup]
16. i[sup]34[/sup] × i[sup]44[/sup]
17. i[sup]50[/sup] + i[sup]40[/sup]
18. i[sup]49[/sup] ÷ i[sup]17[/sup]
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Last edited by Devanté (2006-10-11 06:58:06)
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this is so easy
i^1 = i
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2. i^3 = -1
3. i^0 = 0
4. i^19 = -i
5. 1
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Yes, but can you simplify them instead of answering them?
You can answer them too, if you like.
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that is easy i have done few problems like that in one of my test. very easy but only if you had a calculator.
there is a site if anyone is interested.....
http://www.google.com/intl/en/help/features.html#calculator
Desi
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http://www.algebrahelp.com/calculators/
Desi
Raat Key Rani !
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There is a calculator built into your computer, most likely.
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how can i^3 be -1, if you dont know the value of i?
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how can i^3 be -1, if you dont know the value of i?
we do, i = √(-1)
The Beginning Of All Things To End.
The End Of All Things To Come.
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Kurre wrote:how can i^3 be -1, if you dont know the value of i?
we do, i = √(-1)
why?
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http://www.google.co.uk/search?hl=en&q=sqrt-1&btnG=Search&meta=
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Hmm o_O how do you do the ones with massive powers?
Last edited by Toast (2006-11-02 23:13:59)
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thanks saudi_boy, that's quite clear and a lot simpler than my explanation
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Last edited by saudi_boy (2006-11-02 05:02:55)
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Simplifying Simple i Terms - Intermediate Level
Express in simplest terms, in terms of i.
1. i[sup]1[/sup]
2. i[sup]3[/sup]
3. i[sup]0[/sup]
4. i[sup]19[/sup]
5. (i[sup]12[/sup])[sup]15[/sup]
6. i[sup]16[/sup] + i[sup]11[/sup]
7. i[sup]18[/sup] + i[sup]13[/sup]
8. (i[sup]6[/sup])[sup]30[/sup]
9. i[sup]25[/sup] - i[sup]20[/sup]
10. i[sup]29[/sup] × i[sup]14[/sup]
11. i[sup]23[/sup]
12. i[sup]36[/sup] ÷ i[sup]32[/sup]
13. i[sup]37[/sup] - i[sup]2[/sup]
14. (i[sup]28[/sup])[sup]33[/sup]
15. i[sup]8[/sup]
16. i[sup]34[/sup] × i[sup]44[/sup]
17. i[sup]50[/sup] + i[sup]40[/sup]
18. i[sup]49[/sup] ÷ i[sup]17[/sup]
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Answer,,
1. i
2. -i
3. i^o= 1
4. i^19 = i^3 = -i
5. 1
6. 1 - i
7. i^18 + i^13 = i^2 + i^1 = -1 +i
8. 1
9. i - 1
10. i^29 + i^14 = i^1 + i^2 = -i
11. i^23 = i^3 = -i
12. 1
13. i + 1
14. 1
15. 1
16. -1
17. 0
18. 1
:)
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