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how can i estimate the sine or tangent in a given triangle
and why is the sine of the 30 degrees equal to .5?
thanks
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Your second question is answered about halfway down this page.
The first question is a bit more abstract. Could you elaborate a bit on what you mean, please?
Why did the vector cross the road?
It wanted to be normal.
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the exact question on my homework is: Estimate sinA and tanB in the given triangle ABC
then theres a picture of a right triangle thats labeled with A, B, and C and the 90 degree angle is shown
thats all it says and we never went over anything like this in class so I have no clue what to do
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So maybe you could try to measure angle A (or B). If A is 30 degrees, then you can answer with sin 30 (=0.5), and tan 60 (=√3) (because if A is 30, B has to be 60).
If angle A is something else, maybe you could use your calculator
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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Or, because it's a right-angled triangle, then a possible simpler way would be to measure the sides of the triangle and find their ratios.
A
|\
| \
| \ c
b | \
| \
| \
C ----------- B
a
Sin A in this case would be length a divided by length c, and tan B would be b divided by a.
That might change depending on which angle is the right angle though.
Why did the vector cross the road?
It wanted to be normal.
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