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#1 2006-12-07 23:50:33
- WiZaRd
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?????
How can i type Matrices here in this Forum or how can i write Questions of MAtrices here?
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#2 2006-12-08 00:59:15
- numen
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Re: ?????
I think this is the thread you're looking for 
Check #9 for matrices.
Last edited by numen (2006-12-08 01:01:44)
Bang postponed. Not big enough. Reboot.
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#3 2006-12-08 23:34:45
- WiZaRd
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Re: ?????
thanks i will try it now
Last edited by WiZaRd (2006-12-08 23:36:33)
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#4 2006-12-08 23:44:29
- WiZaRd
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Re: ?????
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#5 2006-12-08 23:46:23
- WiZaRd
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Re: ?????
i can't do that!! help me plzz
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#6 2006-12-08 23:57:17
- Toast
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Re: ?????
Well, that thread should tell you; perhaps you simply made an error.
If you want further reading on LaTeX or to clear up how to program matrices then go to this excellent website (which is a must for your 'favorites'):
http://www.maths.tcd.ie/~dwilkins/LaTeXPrimer/
EDIT: 'Matrices and arrays' shouldn't be far down the page 
Last edited by Toast (2006-12-09 00:19:13)
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#7 2006-12-09 00:03:24
- WiZaRd
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Re: ?????
okay i willl try my best
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#8 2006-12-09 04:03:40
- WiZaRd
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Re: ?????
I finally Got It Yeah Now Prove This Please
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#9 2006-12-09 04:08:14
- krassi_holmz
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Re: ?????
You mean the determinant?
IPBLE: Increasing Performance By Lowering Expectations.
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#10 2006-12-09 06:03:43
- WiZaRd
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Re: ?????
Yes sorry Determinant Actually
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#11 2006-12-09 09:33:07
- Patrick
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Re: ?????
remember you can do greek letters by putting a \ in front of the name of the letter.
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#12 2006-12-09 19:29:39
- WiZaRd
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Re: ?????
Okay So Prove This
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#13 2006-12-09 20:37:55
- Ricky
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Re: ?????
Start off with the definition of a determent, then simply plug and chug.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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#14 2006-12-10 22:32:20
- WiZaRd
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Re: ?????
Solve this i want to see how it works here?
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#15 2006-12-11 05:46:45
- yo mama
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Re: ?????
wut kind of flag is that
#16 2006-12-17 03:17:11
- WiZaRd
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Re: ?????
flag of my country
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#17 2006-12-17 08:03:15
- basmah
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Re: ?????
Are you sure its not this:
because when im trying to solve it im getting negative of the expression
i don't like playing with alpha, beta and gammas so im using
alpha = x beta = y gamma = z
Here it is:
you take the right hand side(RHS) of the expression and then expand it
RHS= (y-x)(z-x)(y-z)
= (yz-yx-xz+x²)(y-z)
= y²z-xy²-xyz+x²y-yz²+xyz+xz²-x²z
(now rearrange them and combine like terms)
= y²z-yz²+xz²-x²z-xy²+x²y
= -1(-y²z+yz²-xz²+x²z+xy²-x²y)
= -1[(yz²-y²z)-(xz²-x²z)+(xy²-x²y)]
=
this is what im getting...so check your question again
Last edited by basmah (2006-12-17 08:04:40)
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