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#1 2006-11-27 07:26:06
- Kiran
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- Registered: 2006-11-15
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is this right way
factor
9x^(2n+3) + 18x^(5n+1)
i did
9*x^n*x^n*x^3 + 9 * 2 *x^n*x^n*x^n*x^n*x^n + x
correct so far?
Live 4 Love
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#2 2006-12-06 13:00:09
- John E. Franklin
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Re: is this right way
Maybe you factor out 9x^(2n+1) since they are smaller than 5n and 3 ??
igloo myrtilles fourmis
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#3 2006-12-07 08:58:35
- LQ
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- Registered: 2006-12-04
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Re: is this right way
factor
9x^(2n+3) + 18x^(5n+1)
i did9*x^n*x^n*x^3 + 9 * 2 *x^n*x^n*x^n*x^n*x^n + x
correct so far?
9x^3*x^2n + 18x*18x^5n
=
9x(x^2*x^2n + 36x^5n)
=
9x*x^2n(x^2 + 36x^3n)
=
9x^(2n+1)(x^2 + 36x^3n)
That's what they mean with factor i think.
I see clearly now, the universe have the black dots, Thus I am on my way of inventing this remedy...
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#4 2006-12-09 04:18:11
- krassi_holmz
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Re: is this right way
LQ, right. Just a little mistake:
Last edited by krassi_holmz (2006-12-09 04:21:08)
IPBLE: Increasing Performance By Lowering Expectations.
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#5 2006-12-09 22:05:37
- LQ
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- Registered: 2006-12-04
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Re: is this right way
soha wrote:factor
9x^(2n+3) + 18x^(5n+1)
i did9*x^n*x^n*x^3 + 9 * 2 *x^n*x^n*x^n*x^n*x^n + x
correct so far?
9x^3*x^2n + x*18x^5n
= *corrected misstake*
9x(x^2*x^2n + 2x^5n)
=
9x*x^2n(x^2 + 2x^3n)
=
9x^(2n+1)(x^2 + 2x^3n)That's what they mean with factor i think.
Thank you for showing me that I errored krassi_holmz.
I see clearly now, the universe have the black dots, Thus I am on my way of inventing this remedy...
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#6 2006-12-17 02:45:12
- krassi_holmz
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Re: is this right way
just having fun!
IPBLE: Increasing Performance By Lowering Expectations.
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