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#1 2006-12-27 03:15:09
- Kiran
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- Registered: 2006-11-15
- Posts: 177
Correct?
solve
7^(2x + 3) = 5^(3x - 1)
so
log7^(2x + 3) = log5^3x - 1)
(2x + 3) log7 = (3x - 1) log5
(2x + 3) (0.84509804) = (3x - 1) (0.698970004)
1.69019608x + 2.53529412 = 2.096910012x - 0.698970004
-0.406713932x = -3.234264124
x = 7.952184249
or
x = 8.0
Last edited by Kiran (2006-12-27 03:15:21)
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#2 2006-12-27 03:40:21
- luca-deltodesco
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- Registered: 2006-05-05
- Posts: 1,470
Re: Correct?
that is correct, but you should keep the numbers in log form until you get to the final step to keep it more accurate.
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