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how many different two player thumb-wrestling teams could be formed from 5 players?
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let them be a->e
ab,ac,ad,ae,bc,bd,be,cd,ce,de = 10 combinations.
Last edited by luca-deltodesco (2006-12-27 11:57:37)
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The End Of All Things To Come.
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Exactly Right.
Also try: Combinations and Permutations Calculator (Order Important: No, Repetition: No), which gives:
"Combinations without Repetition (n=5, r=2)
{a,b} {a,c} {a,d} {a,e} {b,c} {b,d} {b,e} {c,d} {c,e} {d,e} "
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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Yup thats the exact answer i got last night when i was doing it.
but i did it a different way.
i wrote
1 2 3 4 5
and paired it up
like
12
34
45
42
41
and etc.....and there are only 10ways i got
thanks btw
Live 4 Love
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For small problems that works fine.
But then ask how many different 4-player teams could be formed with 40 people, and you find that the mathematics becomes easier.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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is it necessary for simle things to make it on difficult way it is as simple as nCr like so take a right step. definately it will increase the way of thinking for big nos.
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