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The problems is x = 3cos^3(3t)
I got dx/dt = -27sin(3t)cos^2(3t)
I need to simplify this. I tried a few identities but I can't get it simpler and I know there is someway to do it. Someone please help me! Thanks
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no I believe that it. Unless their is something i'm missing, then that is the final answer.
There has to be a way to simplify it with identities. This is from a parametric equation problem. I already solved and simplified the y= equation, I just need this one.
Last edited by aarunt1 (2007-01-16 23:29:45)
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Simplify it how? Do you want it in terms of t instead of 3t? If so, then it's possible, but the result will probably be a lot more complicated than that one.
You need to use the two addition identities:
sin(A+B) ≡ sinAcosB + cosAsinB
cos(A+B) ≡ cosAcosB - sinAsinB
By substituting A=2t, B=t into those, you can convert the 3t's into 2t's and t's, and then by using A=B=t you can convert the 2t's into t's.
The equation will probably look really messy and horrible once you've done that though.
Why did the vector cross the road?
It wanted to be normal.
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Well the problem is The problems is x = 3cos^3(3t) , y=4sin^2(2t) and it wants to know the length of the curve. It seems impossible without dx/dt simplifying down to something small and I figured it should be possible since I can simplify dy/dt
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Hi;
Long time ago!
Just an alternate form.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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