Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2007-02-07 02:38:28

jxharmon
Member
Registered: 2007-01-08
Posts: 104

Need 2nd set of eyes to check plz

10x+2y=7
Y=-5x+3
10x+2(-5x+3)=7
10x-10x+6=7
No solution


I am to solve the system by using either addition or substitution.

If a unique solution does not exist, state whether the system is dependent or inconsistent, this is where I am confused?????????????????

Offline

#2 2007-02-07 03:44:00

Dross
Member
Registered: 2006-08-24
Posts: 325

Re: Need 2nd set of eyes to check plz

jxharmon wrote:

If a unique solution does not exist, state whether the system is dependent or inconsistent, this is where I am confused?????????????????

Two simultaneous equations are inconsistent if there exists no solution - it means that there are no possible values of x and y that mean that both of the equations can hold for those values, hence they are inconsistent with each other.

Two simultaneous equations are dependant if, when you take any x and plug it into both of the equations, you always get the same value for y. This basically means that the two equations are equivalent to each other, but just rearranged a little.

Since the two above equations have no solutions, they are inconsistent.


Bad speling makes me [sic]

Offline

#3 2007-02-07 04:16:29

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,588

Re: Need 2nd set of eyes to check plz

Cool, two parallel lines, off by 1/2 on the vertical... "inconsistent", I'll try to remember that.


igloo myrtilles fourmis

Offline

Board footer

Powered by FluxBB