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one number is 12 more than another. the sum of the smaller number and twice the larger number is 39. find the larger number.
x-12=n
n+2(x)=39 am I on the right track?
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n+2x=39; 2x=39-n; x=39/2-n; and now I am lost what am I doin wrong?
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You're told that the bigger number (x) is 12 bigger than the smaller number (n). You can use this to write x in terms of n.
After that, you can rewrite the equation n+2x = 39 in terms of n only, which will make it a lot simpler.
Why did the vector cross the road?
It wanted to be normal.
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It doesn't matter whether you solve for x or for n first. Once you find one value it's easy to solve for the other. You have the following 2 equations:
n=x-12
n+2x=39
Substitute x-12 for n in the second equation:
x-12+2x=39
3x=51
x=17
Now solve for n:
n=x-12
n=17-12
n=5
For me, that was the easiest way to do it. The approach you were taking was fine too:
n+2x=39
2x=39-n
x=(39-n)/2
Now use this value for x and substitute into your other equation: n = x-12
n=x-12
n=(39-n)/2 - 12
2n = 39-n -24 (multiply each side by 2 to get rid of the fractions)
3n = 15
n =5
Same answer, just not quite as easy.
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