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solve the system by substitution
3x + 6y =o; x=2/3; 3(2/3) +6y =0; 2+ 6 = ) confused???
3x - y = -7 ; x + y = -9; y= -x-9; 3x -x = -7; 2x = -7; x = -7/2 now I'm confused again what in the world am I doin??
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You almost got this one done, just forgot to write down the y with the 6.
Here's you:
3x + 6y =o; x=2/3; 3(2/3) +6y =0; 2+ 6 = )
3x + 6y =o; x=2/3; 3(2/3) +6y =0; 2+ 6y = 0; 6y = -2; y = -1/3
And other one:
You said:
3x - y = -7 ; x + y = -9; y= -x-9; 3x -x = -7; 2x = -7; x = -7/2 now I'm confus
3x - y = -7 ; x + y = -9; y =-x-9; 3x + x + 9 = -7; 4x = -16; x = -4; y = -(-4) - 9; y = -5
That should clear things up a bit. bye.
igloo myrtilles fourmis
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thanks guess I wasn't wotching close enough; could the first one also be done by addition?? if so how does it work??
Last edited by jxharmon (2007-02-10 08:03:11)
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