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ok we know
i° =1
i =i
i² =-1
i³ =-i
and after this it follows a pattern where i^4 equals 1. how could i write a prrof for this
lets just call it, i, and get it over with
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T33N_T1T4N,
i° =1
i =i
i² =-1
i³ =-i
i^4=i² x i² = (-1)x(-1)=1
Since the product of two negative numbers is a positive number.
As a matter of fact, the cycle continues.
i^(4n+1)=i,
i^(4n+2)=-1,
i^(4n+3)=-i
and i^(4n)=1 where n is a whole number.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Just stating it a different way:
And this covers all integers, by the division-remainder theorem.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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ah ok i see. at first i didn't understand where the +1 +2 and +3 came from...but i see that it if i worked backwords...
i^35 35/4=8+3
so i^35= -i
thanks for helping me with that ganesh and ricky
lets just call it, i, and get it over with
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