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If anyone can help....honestly, it would mean so much. I am desperate for help on these questions. I'm sure some of the clever people on this forum can help us unfortunate ones out
1. What is the percentage increase from 2500 to 3300?
2. What is the percentage reduction between 45 and 34?
3. What length is "A"?
4. The table shows the hectares of land mined and rehabilitated at the coal mine. For each of the years, calculate the percentage of land leveled and seeded at the mine.
5. Find the percentage of the total hectares of land leveled (reclaimed) between 1996 and 1999.
If anyone could help me out, it would mean so much, like I said.
Thanks so much for any help.
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Percentage increase/reduction questions generally involve the formula:
So, for 1), the percentage increase is given by (3300 - 2500)/2500 * 100 = 32%.
2) is worked out using the same method, just different values.
3) This question needs Pythagoras. Because the triangle is right-angled, the squares of the smaller sides will add up to the square of the larger one. Therefore, the missing side has a length of √(26² - 24²).
And I'm not sure what 4) is asking, which means that I can't help you with 5) either.
It's another question involving percentages though, so hopefully you'll be able to use the methods from 1) and 2) to help you.
Why did the vector cross the road?
It wanted to be normal.
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I found your answer on the internet.
And I mean exactly your answer, number for number in the same chart.
Your chart in 2nd column doesn't read exactly the same "area levelled reclaimed" vs. "area mine reclaimed"
Last edited by John E. Franklin (2007-02-27 16:19:50)
igloo myrtilles fourmis
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The original article can't be read, but google did display this much.
http://209.85.165.104/search?q=cache:vgoxGZ5TprsJ:info.wlu.ca/~wwwgeog/courses/FW2005-2006/GG254/NumeracyTestSolution%255B2%255D.doc+%22land+levelled%22+%22coal+mine%22&hl=en&ct=clnk&cd=1&gl=us
or click below:
http://209.85.165.104/search?q=cache:vg … cd=1&gl=us
igloo myrtilles fourmis
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So I believe that means that question # 5,
which says,
5. Find the percentage of the total hectares of land leveled (reclaimed) between 1996 and 1999.
Probably means they want 100% times 128.95 divided by 189.13.
So divide 128.95 by 189.13 on your calculator, it will be 0.6 or 0.7 something.
So your answer is 60 or 70 something. Just move the decimal over so 0.6 or 0.7 is 60% or 70%.
Got it??
igloo myrtilles fourmis
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3) This question needs Pythagoras. Because the triangle is right-angled, the squares of the smaller sides will add up to the square of the larger one. Therefore, the missing side has a length of √(26² - 24²).
Ok, so is √(26² - 24²). acceptable as an answer, or does it need to be worked out?
If it does, what is the answer, if you don't mind?
Thanks
(Thanks a lot for all the help so far, aswell)
Last edited by Smokin' (2007-02-28 12:17:19)
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in #3, that doesn't look like any 22 degree angle to me!!
Where'd you get that drawing. It's obviously way off.
With a triangle that badly drawn, how can you
assume any of the angles are 90 or 22.61986 or anything??
Last edited by John E. Franklin (2007-02-28 14:02:28)
igloo myrtilles fourmis
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So the answer to #3 is between 2 and 50, that's my final answer.
igloo myrtilles fourmis
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Ah, the picture's fine. It doesn't claim that it's to scale or anything. The important part is that the right-angle is marked.
To Smokin', I would imagine that you would indeed need to work out the value of √(26² - 24²) to get an acceptable answer. I don't see why you need us to tell you what that is though. It should be more than easy enough to find out by yourself.
I can confirm that it is definitely between 2 and 50 though.
Why did the vector cross the road?
It wanted to be normal.
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On my computer the right angle is not marked, I swear.
igloo myrtilles fourmis
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...Well now I feel very silly. I've been talking about right-angle markings that aren't there.
Still, it's probably safe to assume that that's a right-angle, because we need some form of extra information to work stuff out and that seems to be the most obvious thing.
Why did the vector cross the road?
It wanted to be normal.
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