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One travels company flies three kinds of airplanes: the Airbus 100, the Airbus 200, and the Airbus 300. Each plane is outfitted with tourist, economy, and first-class seats. The number of each kind of seat in the three types of planes is shown below. The second chart lists the number of reservations for its July flight to France. How many of each kind of plane should the company fly to fill all the seats?
Airbus A Airbus B Airbus C
Tourist 50 75 40
Economy 30 45 25
First Class 32 50 30
Category Number of reservations
Tourist Class 305
Economy Class 185
First Class 206
Letter, number, arts and science
of living kinds, both are the eyes.
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This problem is similar to the one you posted earlier about capsules and drugs. It can be solved in the same way as mathsyperson showed.
Here are your three simultaneous equations:
50a + 75b + 40c = 305 [1]
30a + 45b + 25c = 185 [2]
32a + 50b + 30 = 206 [3]
You could simplify if you wanted:
[1] simplifies 10a + 15b + 8c = 61
[2] simplifies 6a + 9b + 5c = 37
[3] simplifies 16a + 25b + 15c = 103
(where a, b and c are the respective airbuses.)
Combine equations and eliminate the variable 'c':
3*[2] - [3] --> 2a + 2b = 8 [4]
5*[1] - 8*[2] --> 2a + 3b = 9 [5]
So, like before, we now have two equations.
[5] - [4] --> b = 1
If you substitute b into either equation [4] or [5], you will be able to find a. Then, using the results for a and b, substitute them into equation [1], [2] or [3] to find c.
So, the airline company should fly three 'A' airbuses, one 'B' airbus, and two 'c' airbuses.
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Thanks a lot
Letter, number, arts and science
of living kinds, both are the eyes.
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even though i was looking solution in matrix form but this helped me alot.
Hi FarazAhmad;
This is what those simultaneous set of linear equations look like in matrix form of Ax = b:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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