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The area of a square field is 5184 m² .A rectangular field ,whose length is twice of its breadth has its perimeter equal to the perimeter of the square field.Find the area of the rectagular field?
your help will be appreciated
Last edited by soha (2007-03-15 19:44:27)
"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"
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the area of the rectagular is 4608.
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how did u get it
"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"
- David O. McKay
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define a that satisfies
a²=5184
4a=2(2a)=2(2a/3+4a/3)
Area of the Rectangle=(2a/3)(4a/3)= (8/9)a²=4608
Last edited by George,Y (2007-03-16 00:29:22)
X'(y-Xβ)=0
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or you may define the length of the two sides of the rectangular as b and 2b
Thus 4a=2(b+2b) solve and get b=2a/3 and 2b=4a/3
X'(y-Xβ)=0
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try the same problem but instead of the perimeter, the diagonal is the same on the square and the rectangle!
(this was the problem i first solved since i thought perimeter meant diagonal )
Last edited by Kurre (2007-03-16 20:37:04)
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i suppose this somewhat related with square and square roots because this question was in squares chapter
"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"
- David O. McKay
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please help me in this , coz it has not gone in my head till now , and you all are explaining , but i am unablle to understand , so wHAT WILL I DO ?
its really very very very very confusing.
"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"
- David O. McKay
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Right, lets start from the beginning.
Let each side of the square be x. Then its perimeter is 4x and its area is x[sup]2[/sup]. We know that x[sup]2[/sup] = . ∴ x = √5184 m = 72 m.
Let the breadth of the rectangular field be y. Then its length is 2y. Its perimeter is 2×(2y+y) = 6y. We want this perimeter to be equal to the perimeter of the other field, i.e. we want
6y = 4x = 288 m
∴ y = 288∕6 m = 48 m
Then the area of the rectangular field is 2y×y = 2y[sup]2[/sup]. Substitute for y and youll get the answer, 4 608 m².
Last edited by JaneFairfax (2007-04-03 01:46:19)
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