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#1 2005-06-11 21:30:37

Lil B
Member
Registered: 2005-06-11
Posts: 2

nth term??? HELP ME PLEASE!!!

Hi i was wondering if anyone could help me with this nth term quadrtic equation i just cant figure it out??
the sequance is 7,22,43,70,103,142,187,238
once again please help me find the correct equation i would be extremelly grateful.

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#2 2005-06-11 22:39:13

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,713

Re: nth term??? HELP ME PLEASE!!!

3x^2 + 6x -2

Lets do some spot-checks:

7,22,43,70,103,142,187,238
1,2  ,3  ,4  ,5   ,6    ,7   , 8

where x=1, y=3 * x^2 + 6 * x -2 = 3+6-2 = 7
where x=4, y=3 * x^2 + 6 * x -2 = 3*16 + 6*4 -2 = 48 + 14 -2 = 70
where x=8, y=3 * x^2 + 6 * x -2 = 3*64 + 6*8 -2 = 192 + 48 -2 = 238

Looks Good !


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#3 2005-06-11 23:14:43

Zach
Member
Registered: 2005-03-23
Posts: 2,075

Re: nth term??? HELP ME PLEASE!!!

Look at Mr. Smug here.


Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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#4 2005-06-12 04:38:49

Lil B
Member
Registered: 2005-06-11
Posts: 2

Re: nth term??? HELP ME PLEASE!!!

WOW!!!
thanks maths is fun!!

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