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Without using calculator , Prove that
(tan20°)×(tan30°)×(tan40°)= (tan10°)
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4sin20sin20sin40tan30
4sin20cos20cos40
=4sin20sin20sin40tan30
sin80
So 4sin20sin20sin40tan30 should be sin10
X'(y-Xβ)=0
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4sin20sin20sin40tan30
4sin20cos20cos40=4sin20sin20sin40tan30
sin80So 4sin20sin20sin40tan30 should be sin10
is this correct?
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I think Ive cracked it.
The triple-angle formula for tan gives
(2)×(3) gives
Now multiply (4) and (1) and the result follows! Woot woot!
Last edited by JaneFairfax (2007-05-23 08:23:27)
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