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y" + y*(y')^3 = 0
Let v = y' therfore v'= f(y.v) which uses variables x, y & z eliminate x by thinking of y as independent via chain rule v*(dv/dy) = f(y.v) There will be two constants in the final result
I having trouble setting up and solving.
Thanks for any help.
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So the original differential equation becomes
If v = 0, then y is a constant function. Otherwise
Hence the solution is
or
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I hate to be ignorant but I don't really follow the first line. And, I missed how y=C.
Can you point me in the right direction. I need to get this down or I will never make it.
Thanks.
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The y = C part comes from
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Makes sense.
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