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Given the function
where a is a constant, . Let be the region bounded by , x-axis and y-axis. Let be the volume obtained when is rotated by about the y-axis. Given that find a.Last edited by ruihan106 (2007-06-05 14:20:40)
.9999999999 = 1
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Draw the function, sketch the volume after rotation.
Slice the volume vertical to x axis and then integrate.
X'(y-Xβ)=0
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Hint
f(x) passes (-a,0) (a,0) and (0,a[sup]2[/sup])
X'(y-Xβ)=0
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For
i got . For i got . The answer provided is. Can anyone check my answer. ThanksLast edited by ruihan106 (2007-06-05 19:11:50)
.9999999999 = 1
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I got
X'(y-Xβ)=0
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The same G.
X'(y-Xβ)=0
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For
i got . For i got . The answer provided is. Can anyone check my answer. Thanks
Your answer for V is wrong. You are rotating about the y-axis, not the x-axis; also, the answer should have a π in it.
Last edited by JaneFairfax (2007-06-06 02:26:24)
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OH.. Thanks a lot. I wrote it as
instead of . Careless mistake...Last edited by ruihan106 (2007-06-06 02:15:56)
.9999999999 = 1
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Glad you sorted out the problem now.
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3 3 3 3 3 =100 Is My Problem Please Solve This By Addition Or Subtraction Or Division Or Multiplication In B/w Thees Numbers Finally I Want Iis The Answers
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Last edited by ruihan106 (2007-06-06 14:05:45)
.9999999999 = 1
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