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Sets A, B, and C have 6 members in common. Sets A and B have a total of 17 members in common. Sets B and C have a total of 10 members in common. If each member of set B is contained in at least one of the other two sets, how many members are in set B?
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Break B into 4 groups:
Those members which are only in B
Those members which are only in A and B
Those members which are only in A and C
Those members which are in A, B and C.
If you can find out how many members are in each of those groups, you can add them up and get the total.
You were told there were 0 members which are only in B and 6 members which are in A, B and C. A and B have 17 members in common but 6 are also in C so there are 11 members which are in A and B but not C. B and C have 10 members in common but 6 of those are also in A. So there are 4 members in B and C but not A.
0 + 11 + 4 + 6 = 21
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Thank You pi man
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