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#1 2007-08-10 04:45:29
- misdamike55
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- Registered: 2007-08-10
- Posts: 1
in need of help
Z Is A Standard Normal Random Variable
How Do You Do This One
P(z>-2.08)
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#2 2007-08-10 05:55:38
- mathsyperson
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- Registered: 2005-06-22
- Posts: 4,900
Re: in need of help
P(Z>-2.08) = P(Z<2.08).
You can look up that second expression in a table of Z-values.
Why did the vector cross the road?
It wanted to be normal.
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#3 2007-08-10 06:10:20
- misdamike55
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- Registered: 2007-08-10
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Re: in need of help
its that easy
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#4 2007-08-10 10:33:35
- MathsIsFun
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- Registered: 2005-01-21
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Re: in need of help
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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#5 2007-08-10 22:34:25
- mathsyperson
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- Registered: 2005-06-22
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Re: in need of help
That's interesting. The tables I've seen before give probabilities of Z ≤ x, where x is some positive number.
Your one gives P (0 ≤ Z ≤ x) instead. Your way is probably a bit more useful, actually.
Why did the vector cross the road?
It wanted to be normal.
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