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#1 2007-08-12 20:35:29
- mathsux
- Member
- Registered: 2007-08-06
- Posts: 10
Graph of y = x^2 + 6x + 2
Okay,
I need a non-calculator method for this problem.
I can work out the Turning point and put it into TP form, but I have massive difficulty finding the X-intercepts.
TP Form: y = -(x-3)^2 + 11 ---> Turning Point = (3, 11)
Y Intercept ---> y = 2
I just need the X-Intercepts!
PLz help.
Thanx.
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#2 2007-08-12 21:08:54
- JaneFairfax
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- Registered: 2007-02-23
- Posts: 6,868
Re: Graph of y = x^2 + 6x + 2
Set y = 0 and solve the quadratic equation.
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#3 2007-08-12 21:22:22
- mathsux
- Member
- Registered: 2007-08-06
- Posts: 10
Re: Graph of y = x^2 + 6x + 2
I think I've done something wrong...I must've. If I check using the calculator the graph of -x^2+6x+2=y is like the opposite of the graph of -(x-3)^2+11=y (inverse)
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#4 2007-08-12 21:28:03
- mikau
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- Registered: 2005-08-22
- Posts: 1,504
Re: Graph of y = x^2 + 6x + 2
You mean upside down? thats definitly not the case. They both point down (lead coefficient is negative).
A logarithm is just a misspelled algorithm.
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#5 2007-08-12 22:49:15
- JaneFairfax
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- Registered: 2007-02-23
- Posts: 6,868
Re: Graph of y = x^2 + 6x + 2
Theyre the same.
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