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Let f(x) = { x²  if x is rational
               { 0  if x is irrational                
Prove that  lim  f(x) = 0
                x->0
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Why did the vector cross the road?
It wanted to be normal.
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Given epsilon> 0, take delta = sqrt(epsilon).  If |x- 0|= |x|< delta, then either
1.  x is rational, in which case |f(x)- 0|= |x^2- 0|< delta^2= epsilon
2.  x is irrational, in which case |f(x)-0|= |0- 0|< epsilon.
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