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lim θ->0 (cosθ-1)/(sinθ)
Can i get some help on this question please
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You can use LHòpitals rule. The answer is 0.
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thanks. Can you give a example for LHòpitals rule plz?
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Examples
1.
apply LHòpitals rule.
2. note:Applying the rule a single time still results in an indeterminate form. In this case, the limit may be evaluated by applying l'Hôpital's rule three times:
Last edited by saudi_boy (2007-10-09 21:53:09)
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Do we really need L'Hôpital's Rule?
What about if you multiply top & bottom by
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Do we really need L'Hôpital's Rule?
What about if you multiply top & bottom by
?
Unless Im missing something, it makes no difference.
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Multiplying by Sin(theta) works too.
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I see, thanks. Although LHòpital works just as quickly so theres nothing wrong with that method either.
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Of course there's nothing wrong, it's more interesting to compute limits without him.
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