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A rotating pail of water with an angular velocity w has a surface curving up from the centre to the outer edge. Find the shape of the surface. The slope of the surface is dy/dx = tan(theta) at position x is y (= function of x) is the shape of the surface. You must resolve forces to find tan(theta) as a function of x, and then solve for the height, y, as a function of x.
If the pail rotates once per second, and has a diameter of 0.45 m, how high above the centre is the outer edge?
All I see is that w = 2pi rad/sec and r = 0.225 m.
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