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i have this system of equations where the augmented matrix is
(a-9) 4 1 0
-20 (a+9) 3 0
24 -12 (a-6) 0
can anyone help me put this in reduced echelon form??
i dont know what to do to the matrix to get a 1 in the leading row! please help!!!
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this takes time but you can do it. What you can do first is you can divide the top row by (a-9), the first element in the first row will therefore become (a-9)/(a-9) which is 1.
A logarithm is just a misspelled algorithm.
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ive got it this far but now am struggling to complete row echelon form is this correct so far anyone??
1 4/(a-9) 1/(a-9)
0 a^2-12a+11 a^2-12a+23
0 12a-204 a^2-15a+30
please help!!!
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