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#1 2007-11-20 03:41:38
- James000
- Guest
computing integral
i'm not sure how to approach this. any help would be greatly appreciated!
integral of e^[-(x-1/2z)^2] dx
#2 2007-11-20 03:57:30
- mikau
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- Registered: 2005-08-22
- Posts: 1,504
Re: computing integral
is that z supposed to be an x?
A logarithm is just a misspelled algorithm.
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#3 2007-11-20 04:09:47
- James000
- Guest
Re: computing integral
No, it's supposed to be a z (a constant).
#4 2007-11-22 08:00:37
- freddogtgj
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- Registered: 2006-12-02
- Posts: 54
Re: computing integral
Can you not just expand the bracket so you are left with
and then use the rule for integrating e?
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#5 2007-11-22 09:25:46
- Krizalid
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- Registered: 2007-03-09
- Posts: 51
Re: computing integral
James000 wrote:
i'm not sure how to approach this. any help would be greatly appreciated!
integral of e^[-(x-1/2z)^2] dx
Sure. This makes sense if
That means that we're talking about the famous gaussian integral:
This can be proven in many ways. Polar transform is the common one.
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