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Evaluate
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Id suggest changing to polar co-ordinates. This looks like it might be easier to integrate in polar form.
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I'm definitely rusty on double integrals, but I think you just evaluate one integral at a time and consider all other variables as constants. For this problem, use substitution:
This substitution removes that ugly square root from the denominator, but we're left with an extra x. Solving for x in terms of u gives us
We're now left to evaluate the following integral:
Evaluate the inside integral, pretending that y is a constant. You should end up with a function in terms of y, which you then integrate over 0 to 1 for the final answer.
Edit: Or use Jane and Krizalid's method, it looks much more clean.
Last edited by TheDude (2007-11-23 04:55:55)
Wrap it in bacon
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Id suggest changing to polar co-ordinates.
To do that, split the original square into two triangles:
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