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hey i have the differential equation
y''-5y'+6y=10cosx
im supposed to solve this, so far i have done:
solve y''-5y'+y=0 to get the CF trying y=e^(kx)
y'=ke^(kx) y''=k^2e^(kx)
the auxillary equation is k^2-5k+6=0
Thus the CF is y=Ae^3x +Be^2x
Iv got to continue solving this equation does anyone know what i could set y to equal to find the PI (particular integral) please help!!!
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Try
.Last edited by JaneFairfax (2007-11-27 09:06:37)
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