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without l hopetal
find
when x-->0
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are you allowed to assume lim sin(x)/x = 1? if so
lim (x - sin(x))/x^3 = lim (1/x^2) - lim(1/x^2)*lim sin(x)/x = lim (1/x^2) - lim (1/x^2)*1 = lim (1/x^2 - 1/x^2) = lim(0) = 0.
i THINK thats right.
A logarithm is just a misspelled algorithm.
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NO! THAT IS WRONG!
You can only use the rule
if both the limits
and exist separately!!In the case of
, does not exist! So how the hell can you sayThat is totally rubbish, man!!
The correct answer is
Last edited by JaneFairfax (2007-11-25 10:29:18)
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Apply LHôpitals rule three times.
no need to get so angry also, he said he is not allowed to use l'hopitals rule
The Beginning Of All Things To End.
The End Of All Things To Come.
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Sorry, I should have read Tonys post more carefully.
Well, then I dont know how to do it, if not by LHôpitals.
Last edited by JaneFairfax (2007-11-25 10:32:57)
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Thus,
Last edited by tony123 (2007-11-30 10:43:51)
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Just to ask, do you know the answers to all your questions at the time you ask them?
The way you present your questions with little else said, and how you sometimes answer them yourself after a while suggests that instead of needing help, you're just giving us puzzles to do.
Not that that's a bad thing, but if that's the case then you should start your own exercises thread.
Why did the vector cross the road?
It wanted to be normal.
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where as by Taylor's theorem.Thus,
.
You stole this from a guy of another forum, what a shame.
You didn't even change any word.
Last edited by Krizalid (2007-12-01 01:49:23)
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Just to ask, do you know the answers to all your questions at the time you ask them?
perhaps not always, i sometimes start a thread with a question, but while waiting for any replies i continue to work on the problem myself, and if i have a revalation, ill update the thread with it.
Last edited by luca-deltodesco (2007-12-01 01:53:30)
The Beginning Of All Things To End.
The End Of All Things To Come.
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Sorry, I should have said that I was asking Tony, because it looks like he's posting questions that he already knows the answers to.
Your way is fine, because you genuinely want help at the time when you ask the question, and it just happens that the person who helps is yourself.
Why did the vector cross the road?
It wanted to be normal.
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tony123 wrote:where as by Taylor's theorem.Thus,
.You stole this from a guy of another forum, what a shame.
You didn't even change any word.
Also,
as is wrong! What he means is , not . For .Last edited by JaneFairfax (2007-12-01 06:15:39)
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Welcome Youth
I have three other solutions to this problem
There is one other forums which he introduced this solution
To discuss this solution
And try to acquire other ideas
JaneFairfax im not a charlatan
Krizalid im not stole but i have three other solutions to this problem
Thank you for all
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Okay, Im sorry. I take it back.
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