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#1 2007-11-27 19:34:18

haruka-san
Member
Registered: 2006-11-08
Posts: 205

help!!!!!asap

prove that

one over square root of two pi times the integral of e raise to negative one half x squared, dx from positive infinity to negative infinity is equal to one.

big_smile


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#2 2007-12-01 08:37:22

Pratheepa
Member
Registered: 2007-12-01
Posts: 5

Re: help!!!!!asap

e raise to the negative power of half x squared will lead to 1 as x goes to infinity because negative half of x squared will become zero, e raised to the power of zero is one....so the answer should be one over square root of two pi.

i think thats correct if i had not mistaken the question

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#3 2007-12-01 10:49:17

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: help!!!!!asap

http://z8.invisionfree.com/DYK/index.php?showtopic=136

So

If you use the substitution

you should get the answer to your question.

Last edited by JaneFairfax (2007-12-01 10:51:02)

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