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great things come from great minds
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I'm guessing that's
.If so, then that's the same as
.So now you solve
or, alternatively, .Why did the vector cross the road?
It wanted to be normal.
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my math teacher says that that that should not be in my lessson i ttake it online and she says thatis too advanced the site it is on is www.auroralearning.com you cant get on with out a password but hve you evey heard of it she also says that the problem it that the question it like a algabra 2 question
great things come from great minds
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That is a tough one for pre-algebra if you haven't learned the laws of rational exponents. Here's another way to look at it:
If you know the rules of rational exponents, then:
(³√k)² = (³√k)*(³√k)This part you can use some reasoning for. "k" should be equal to its cube root * its cube root * its cube root, right?
So if the problem above shows that cube root k * cube root k * -2 = k, then that must mean -2 is the cube root of k.
That then means (-2)³ = k, or -2*-2*-2 = -6 = k.
EDIT: As per below, (-2)³ is, in fact, -8, not -6.
Last edited by NullRoot (2007-12-07 11:43:50)
Trillian: Five to one against and falling. Four to one against and falling Three to one, two, one. Probability factor of one to one. We have normality. I repeat, we have normality. Anything you still cant cope with is therefore your own problem.
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That then means (-2)³ = k, or -2*-2*-2 = -6 = k.
-6? typo i'm guessing.. should be -8.
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Yep. Well spotted
I still get credit for solving for k without actually doing anything more than rearranging the equation, though, right?
Last edited by NullRoot (2007-12-07 11:42:45)
Trillian: Five to one against and falling. Four to one against and falling Three to one, two, one. Probability factor of one to one. We have normality. I repeat, we have normality. Anything you still cant cope with is therefore your own problem.
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