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hey can anyone help me prove that the sequence {an} given by
Last edited by EMPhillips1989 (2008-02-04 08:10:15)
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By definition of convergence:
So basically, we want to prove that 1/N < ε, for any value that ε might take, as long as N is big enough (because if n>N then 1/n <1/N and so 1/n < ε).
Rearranging this gets that N > 1/ε.
So as long as an N exists such that it's bigger than 1/ε, then 1/n does indeed converge to 0.
The Archmides Principle says that given any real number, a natural number exists that is bigger than it. Kind of obvious, but it's the fact we need here.
So then you set N equal to this number and that proves convergence.
Why did the vector cross the road?
It wanted to be normal.
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Just to tidy up some loose strands in the statement of the definition:
There.
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Sorry. I was concentrating so much on getting my LaTeX sorted that I didn't check if it said what I wanted it to.
Why did the vector cross the road?
It wanted to be normal.
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