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hey can anyone help me prove that the sequence
any advise would be much appreciated!!!
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Consider the sum of the first k+1 terms:
S := 1 + 1/2 + 1/4 + ... + 1/(2^k)
Now look at 2S.
This is 2 + 1 + 1/2 + ... + 1/(2^(k-1)).
Taking S away from 2S gives S = 2 - 1/(2^k).
1/(2^k) goes to 0 as k gets large, and you're left with 2.
Why did the vector cross the road?
It wanted to be normal.
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Look up the phrase "geometric series" on google.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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S = 1 + 1/2 + 1/4 + 1/8 + ...
S/2 = 1/2 + 1/4 + 1/8 + 1/16 + ...
S - S/2 = 1
S/2 = 1
S = 2
Last edited by Daniel123 (2008-02-11 11:34:26)
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The series is geometric with first term 1 and common ratio ½; hence the sum is
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