You are not logged in.
Pages: 1
I need to make y as the subject of the following question:
Any suggestions?
Thanks in advance!
Offline
Completing the square looks like your best option. The quadratic formula works too, but it's a nice one to complete the square with so I'd do it that way.
It looks like y's going to be complex for nearly all values of x though.
Why did the vector cross the road?
It wanted to be normal.
Offline
I get
by completing the square.. not sure if that's allowed. :SEDIT: Ahh you beat me to it. Now I know it's OK I'll show my working:
Last edited by Daniel123 (2008-02-17 12:29:37)
Offline
Don't forget the ± in front of the root. [/picky]
Why did the vector cross the road?
It wanted to be normal.
Offline
It's late.. let me off
Offline
of course...we have an equation of a circle in there as well!
Offline
Well, sort of. The equation works out as x² + (y+2)² = 0, so you get a circle centred at (0,-2) with radius 0.
But as the radius is 0, it's really just a point.
Why did the vector cross the road?
It wanted to be normal.
Offline
Pages: 1