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Prove that m^2 - 25m > 0 for all m>25
Proof by induction:
Basic step:
Assume P(m): m^2 - 25m > 0 for all m>25
Prove P(m+1): (m+1)^2 - 25(m+1) > 0
Induction step: P(m+1): (m+1)^2 - 25(m+1)= m^2 - 25m + 2m - 24 This is where I am stuck! I don't know what to do from here.
Could someone please help?
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First, dont forget to show that the statement is true for the first value, in this case m = 26. Although it doesnt matter whether this is done before or after the inductive step, people tend to forget it if they leave it till later; therefore it is good commonsense practice to make a habit of doing this before the inductive step.
For the inductive step, you have
You know that m[sup]2[/sup]−25m > 0 by the inductive hypothesis; for the other half,
Hence
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Thank you so much this was a great help!
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Hi;
Or you could try:
Which is clearly true for m>25.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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