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A(7,2) and C(1,4) are two vertices of a square ABCD
(a) Find the equation of the diagonal BD.
(b) Find the coordinates of B and D.
I have answered (a), but i cant seem to get (b), can someone please show me how to get (b). thanks=)
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-Galileo Galilei
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A = (7,2)
C = (1,4)
im not sure how you are meant to work it out. but taking the midpoint of AC = (4,3). take the vector from the midpoint to A and you have (3,-1). which if you rotate 90 degrees anticlockwise is (1,3). which if you add onto midpoint gives you B or D whichever way you want to have the vertices ordered, and subtracting from midpoint will give the other point.
i.e. (4,3)+(1,3) = (5,6) lets say this is B
(4,3)-(1,3) = (3,0) lets say this is D
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The End Of All Things To Come.
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....x..6
.......5
x......4
...c...3
......x2
.......1
..x....0
1234567
I can see it right because
I have a fixed space font
over-ride option in my
browser.
Last edited by John E. Franklin (2008-03-13 10:45:16)
igloo myrtilles fourmis
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Putting things in code is a good way of making sure you get uniform spacing.
....x..6
.......5
x......4
...c...3
......x2
.......1
..x....0
1234567
Why did the vector cross the road?
It wanted to be normal.
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too bad the x/y scale is still off
6 . . . . . B . .
5 . . . . . . . .
4 . C . . . . . .
3 . . . . M . . .
2 . . . . . . . A
1 . . . . . . . .
0 . . . D . . . .
. 0 1 2 3 4 5 6 7
Last edited by luca-deltodesco (2008-03-13 10:58:04)
The Beginning Of All Things To End.
The End Of All Things To Come.
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I did it a little different but you get same result.
First of all I found the distance between A and C to be:
so since this is the diagonal it means that:
Since this is a square then BC and BA have to be of same length so we let u = BC = BA so it becomes
So you know that the length of the sides of the square are sqrt(20). In this way you could find points B and D knowing the distance from A and C is sqrt(20) etc....I guess I overcomplicated this but thats how I got it.
Last edited by LuisRodg (2008-03-13 11:10:16)
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