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Hi guys, I have a couple of bonus questions that would help me boost my grade in this class.
1. A function :R->R has a PROPER RELATIVE MAXIMUM VALUE at c if there exists d>0 such that f(x)<f(c) for all x that satisfy 0<|x-c|<d. Prove that the set of points at which has a proper relative maximum value is countable.
2. Determine whether the sequence{((-3)^n)/n!} converges and give a proof of your conclusion.
Thanks guys
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2. I'm not going to give a rigorous proof for this, but I will tell you that it converges. This is easy to see if you define the sequence recursively:
As you can see, after n = 2 every successive value will be equal to the previous value multiplied by a number whose absolute value is less than 1. The value of the sequence will bounce between positive and negative numbers, but it will converge to 0. I leave the proof to you.
Wrap it in bacon
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1. A function :R->R has a PROPER RELATIVE MAXIMUM VALUE at c if there exists d>0 such that f(x)<f(c) for all x that satisfy 0<|x-c|<d. Prove that the set of points at which has a proper relative maximum value is countable.
This is one of those questions which are intuitively obvious but present such a challenge to prove. I can only suggest using the metric-space properties of the real numbers. Try proving that the set of points at which has a proper relative maximum value is nowhere dense in R. Countability should follow from the fact that all nowhere-dense subsets of R are countable. (Are they? I think so anyway. )
Last edited by Muggleton (2009-02-15 02:25:35)
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1. A function :R->R has a PROPER RELATIVE MAXIMUM VALUE at c if there exists d>0 such that f(x)<f(c) for all x that satisfy 0<|x-c|<d. Prove that the set of points at which has a proper relative maximum value is countable.
Actually, this problem isn't too bad if you're allowed to know that the real line is 2nd countable. But a step in the right direction either way is to prove:
Let c be a proper relative maximum value. Then there exists d > 0 such that f(x) is not a proper relative maximum value for all x in (c-d,c)U(c, c+d)
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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