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#1 2008-05-08 01:28:27

Melllyy
Guest

Recursive formula

Can someone please show me how to do these. i keep getting the wrong answer

T(n+1) = 3 x Tn x 2^n

a) By substituting n=2 into the rule determine T3... should equal 36

b) By substituting n=3 into the rule determine T4... should equal 864

#2 2008-05-08 02:49:53

TheDude
Member
Registered: 2007-10-23
Posts: 361

Re: Recursive formula

I don't understand your question.  Are you trying to find the base value of T, like T(1)?  Or are you trying to find a non-recursive definition of T(n)?

If it's the first, the problem is easy.  You know T(3) = 3 x T(2) x 2^2 = 3 x 4 x T(2) = 36, so T(2) = 3.  Using this same method you can find that T(1) = 1/2.

If you need a non-recursive definition of T(n), try looking backwards.  What I mean is to do something like this:


The pattern here is pretty easy to see.  We have 3 raised to the power of n-1 at the start.  We then have 2 raised to the power of n^2 - (sum from i = 1 to n of i).  This is then multiplied by our base T(1), which we know from above is 1/2.  This leaves us with


Let's check that this is right.  For T(1) we get 3^0 x 2^(-1) = 1/2.  For T(2) we get 3^1 x 2^0 = 3.  For T(3) we get 3^2 x 2^2 = 36.  And finally, T(4) = 3^3 x 2^5 = 864, all of which are what we expected.


Wrap it in bacon

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#3 2008-05-08 03:22:00

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: Recursive formula

another way of doing it

Last edited by Dragonshade (2008-05-08 03:22:53)

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