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#1 2008-05-14 06:00:14
- Hopecantid
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- Registered: 2008-04-08
- Posts: 13
Trig Equation
Solve for the following equation for
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#2 2008-05-14 06:28:26
- mathsyperson
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- Registered: 2005-06-22
- Posts: 4,900
Re: Trig Equation
Multiply everything by cosθ, and then you can get a quadratic equation in terms of sinθ.
Why did the vector cross the road?
It wanted to be normal.
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#3 2008-05-14 06:41:47
- Hopecantid
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- Registered: 2008-04-08
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Re: Trig Equation
Multiplied by
gives:Not sure what to do next...
Last edited by Hopecantid (2008-05-14 06:43:18)
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#4 2008-05-14 06:43:45
- mathsyperson
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- Registered: 2005-06-22
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Re: Trig Equation
Write cos²θ in a different way.
Why did the vector cross the road?
It wanted to be normal.
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#5 2008-05-14 06:51:55
- Hopecantid
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- Registered: 2008-04-08
- Posts: 13
Re: Trig Equation
Multiplied by
gives:So
orIs that right?
Last edited by Hopecantid (2008-05-14 06:52:31)
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#6 2008-05-14 07:05:11
- mathsyperson
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- Registered: 2005-06-22
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Re: Trig Equation
Looks perfect to me. 
Why did the vector cross the road?
It wanted to be normal.
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#7 2008-05-14 07:06:14
- Hopecantid
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- Registered: 2008-04-08
- Posts: 13
Re: Trig Equation
Thank you for the help!
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#8 2008-05-14 08:13:06
- Kurre
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- Registered: 2006-07-18
- Posts: 280
Re: Trig Equation
Is that right?
Almost. neither of sec and tan are defined for 90°, so that one doesnt work.
Last edited by Kurre (2008-05-14 08:13:51)
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