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how do i solve the following equation?
(9/x) + (3/x-2) = 18/ x(x-2)
do i move everything to one side and find common denominator, or do i cross multiply?
hope someone can help me
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(9x-18+3x)/x(x-2) = 18/ x(x-2)
The base is now the same so u can cancel them off
(12x-18)= 18
x = 3
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Just be careful when cancelling the denominator like that. It doesn't matter here, but if you do it blindly then you might run into problems.
For example, if the question was (9/x) + (9/x-2) = 18/ x(x-2), then your method would eventually tell you that 18x = 36, which means that x=2. But in the original question, making x=2 causes division by 0.
Why did the vector cross the road?
It wanted to be normal.
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In mathsy's case
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