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How do I find the Limit for a function F(x)= -3x +2
Book studying isn't going too well
I am a mathemagician. You ask why? I point up
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Is that the whole question? (to me at least) that doesn't make much sense.
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Unfortunately yes it is thats why I'm pretty confused because this how its asked.
Limits and Funtions
For each function, find lim f(x+Δx)-f(x)
Δx->0 --------------
Δx
1. f(x)= -3x + 2
2. f(x)= x^2
and so on.....
I am a mathemagician. You ask why? I point up
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Well I wanted what x tended to! So in other words it wants you to differentiate from 'first principles'. How far have you got?
You can look below and apply the same steps to the other questions.
Last edited by Daniel123 (2008-08-08 19:03:34)
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So we're practically subtracting "f" by one time so like
f(x)= X^2 + 14
will end up with
lim x because everything else would be cancelled right?
I am a mathemagician. You ask why? I point up
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It sometimes gets more complicated than the one Daniel did, so you can't assume things like that.
f(x) = x² + 14 would be differentiated like this:
Why did the vector cross the road?
It wanted to be normal.
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Hey Kurtz, how do you do it?
π≈ 3.141 592 653 589 793 238 462 643 383 279 502 884 197 169 399 375 105 820 974 944 592 307 816 406 286 208 998 628 034 825 342 117 067 982 148 086 513 282 306 647 093 844 609 550 582 231 725 359 408 128 481 117 450 284 102 701 938 521 105 559 644 622 948 954 930...
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Have you check the "hidden text" given by Daniel and Maths up on top it should help you its done step by step using the limit formula. Just click on it and study it but then it wont help on all of the problems.
So I have one question how would I solve something such as
f(x)= -x² - x + 1 and f(x)= √ x
I am a mathemagician. You ask why? I point up
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Doh... Yeah clicking on Hidden Text helps a lot lol.... Thanks
π≈ 3.141 592 653 589 793 238 462 643 383 279 502 884 197 169 399 375 105 820 974 944 592 307 816 406 286 208 998 628 034 825 342 117 067 982 148 086 513 282 306 647 093 844 609 550 582 231 725 359 408 128 481 117 450 284 102 701 938 521 105 559 644 622 948 954 930...
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f(x) = -x² - x + 1 should be no problem if you understand how I did x² + 14 above.
f(x) = √x is harder though, because it wants you to find:
Unlike the previous examples, √(x+δ) can't be expanded nicely and so it's quite a nasty expression. The function is easy enough to differentiate, but I don't see how to do it from first principles.
Why did the vector cross the road?
It wanted to be normal.
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deriving from the derive definition of f(x)=√x you do like this:
(f(x+h)-f(x)/h) = √(x+h)-√(x)/h, then you multiply with (√(x+h)-√(x)) making it all (√(x+h)+√(x))*(√(x+h)-√(x)) / h*(√(x+h)+√(x)) = (x+h-x) / (h*(√(x+h)+√(x))) = 1 / (√(x+h)+√(x)).
then we make h go towards zero.
f'(x)=lim_h-->0(1/(√(x+h)+√(x)) = 1 / (√(x) + √(x)) = 1 / 2*√(x)
f(x)=√(x) gives f'(x)= (1/(2√(x)))
Last edited by makar92 (2008-08-11 03:00:46)
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by using the variable "h" you are referring to {\delta} right?
Last edited by Kurtz (2008-08-11 10:05:39)
I am a mathemagician. You ask why? I point up
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Yeah, it doesn't matter what variable is used for the limit. I used delta because Daniel already did, but h is used commonly as well.
Why did the vector cross the road?
It wanted to be normal.
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How do I find the Limit for a function F(x)= -3x +2
Book studying isn't going too well
i'll have to agree with daniel
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how do i explain BODMAS?:{
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